-x+(x^2-2)/(x+1)=9

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Solution for -x+(x^2-2)/(x+1)=9 equation: 



-x+(x^2-2)/(x+1)=9

We move all terms to the left:

-x+(x^2-2)/(x+1)-(9)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R



We add all the numbers together, and all the variables

-1x+(x^2-2)/(x+1)-9=0

We multiply all the terms by the denominator


-1x*(x+1)+(x^2-2)-9*(x+1)=0

We multiply parentheses

-x^2-x+(x^2-2)-9x-9=0

We get rid of parentheses

-x^2+x^2-x-9x-2-9=0

We add all the numbers together, and all the variables

-10x-11=0

We move all terms containing x to the left, all other terms to the right

-10x=11

x=11/-10

x=-1+1/10

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